Sum of even valued numbers in Fibonacci series
Filed in Code Snippets on Mar.25, 2010
Up to 4 million.
int f1 = 0;
int f2 = 1;
int temp = 0;
int sum = 0;
for (int i = 0; sum < 4000000;i++)
{
temp = f1 + f2;
f1 = f2;
f2 = temp;
if (f2 % 2 == 0)
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